Thursday, November 29, 2018
2BHK HOUSE PLAN IN VILLAGE||37×34 MODERN HOUSE🏡
https://m.youtube.com/watch?feature=youtu.be&v=8aE6xNpwDk8
2BHK HOUSE PLAN IN VILLAGE||37×34 MODERN HOUSE🏡
Sunday, November 25, 2018
Saturday, November 24, 2018
Concrete Mix Design
Mix Design of Concrete (M-35) :
1.
Characteristic Strength =35 N/mm2
2.
Target mean strength at 28 days as per Morth
,table 1700-3A =47 N/mm2
3.
Maximum Size of aggregate =20mm
4.
Type of Expose-Normal
5.
Degree of Quality Control-Good
6.
Minimum Cement content as per Morth,Table
1700-3A =400 kg/mm3
7.
Maximum water cement ratio as per morth,table
1700-3A---=0.45
8.
Air entrapped as per IS: 10262………=2.0%
9.
Grade of concrete-M35
10.
Workability required in terms of slump at site
as per Morth, Table 1700-3 = 150 to 200 mm
11.
Cement Used Dalmia konarak OPC 53 Grade (IS:
12269-2013)
Coarse Aggregate:
As we will use Coarse Aggregate
20mm & 10mm (Normal Size), So we can have to satisfy
combined grading
criteria IS :383,Table -2. The proportions of Coarse aggregate and Fine
aggregate are CA : FA=60:40 & CA1 (20mm) : CA2 (10mm) =50:50
20mm (Pakur Varity) Specific
Gravity= 2.87
10mm (Pakur Varity) Specific
Gravity= 2.83
Specific Gravity of Fine Aggregate=2.72
Specific
Gravity of Cement=3.15
Water=1
CA:FA=60:40,CA1:CA2=50:50
W/C Ratio= 0.42
Cement =450 kg/m3
Water=450 x 0.42=189 kg/m3
For slump 175mm water content increased upto 15 %=189+15% of
189=217.35 lt/m3
Super Plasticizer (Admixture) @ 0.8% was taken by weight of cement=450 x
0.8%=3.6 kg/m3
As super Plasticizer used the water content can be reduced 10%
Now water content is = 217.35 x 0.9=195.615 Lt
Now, Volume of Cement
=450/3.15 x 1/1000 =0.142 m3
(Where, Weight of Cement=-450kg,Specific Gravity of cement =3.15 )
Volume of water
=195.615/1 X 1/1000 = 0.195 m3
Volume of Super
Plasticizer = 3.6/1.11 X 1/1000 =0.003 m3
(Where, Weight of Super Plasticizer=3.6kg, specific
gravity of S.P.=1.11 )
Volume of air Entrapped
@ 2% =0.02 m3
Total Volume=(0.142+0.195+0.003+0.02)=0.360
m3
Volume of all in
aggregate =(1 – 0.360)=0.64 m3
Mass of CA =0.64 x
2.85 x 0.60 x 1000=1094.40 Kg
(Where, Vol of all in aggregate =0.64,Specific
gravity of CA =2.85, CA : FA = 60: 40)
Mass of FA = 0.64 x
2.72 x 0.40 x 1000 = 696.32 kg
(Where, Vol of all in aggregate =0.64,Specific gravity of
FA =2.72, CA : FA = 60: 40)
Now,
Cu.m Before Moisture
Correction,
Cement= 450kg
20 mm Aggregate=
547.20 kg
10 mm Aggregate=
547.20 kg
Fine aggregate=
696.32 kg
Water = 195.615 kg
Super plasticizer
= 3.6 kg
Thursday, November 22, 2018
Low cost 3bhk house plan||1355 sqft house plan
https://m.youtube.com/watch?v=-toCTZURnz0&feature=youtu.be
Low cost 3bhk house plan||1355 sqft house plan
Low cost 3bhk house plan||1355 sqft house plan
24×42 south face 2bhk house🌆 plan||low cost House plan||890 sqft house design🏙️
https://m.youtube.com/watch?v=cJ0D7RE-ykg&feature=youtu.be
24×42 south face 2bhk house🌆 plan||low cost
House plan||890 sqft house design🏙️
Tuesday, November 20, 2018
3D VIEW 3BHK HOUSE PLAN||38×40 FEET HOUSE DESIGN 🏙️🏙️
https://m.youtube.com/watch?feature=youtu.be&v=1KJ43OnxIyY
3D VIEW 3BHK HOUSE PLAN||38×40 FEET
HOUSE DESIGN 🏙️🏙️
20×46 2BHK MODERN HOUSE PLAN||930 SQFT|🌆🌆🌆🌆🌆🌆🌆🌆🌆🌆🌆🌆🌆🌆🌆🌆🌆🌆🌆
https://m.youtube.com/watch?v=Km8OHkOn27s&feature=youtu.be
20×46 2BHK MODERN HOUSE PLAN||930 SQFT|🌆🌆🌆🌆🌆🌆🌆🌆🌆🌆🌆🌆🌆🌆🌆🌆🌆🌆🌆
20×46 2BHK MODERN HOUSE PLAN||930 SQFT|🌆🌆🌆🌆🌆🌆🌆🌆🌆🌆🌆🌆🌆🌆🌆🌆🌆🌆🌆
43×28 2bhk house plan||low cost house plan 🏨
https://m.youtube.com/watch?feature=youtu.be&v=7lXOnbS1NAk
43×28 2bhk house plan||low cost house plan 🏨
43×28 2bhk house plan||low cost house plan 🏨
Thursday, November 15, 2018
21'×42' house 🏬plan 2bhk||low cost Building plan🏯🏯
https://m.youtube.com/watch?v=EowWJPc0xK4&feature=youtu.be
21'×42' house 🏬plan 2bhk||low cost
Building plan🏯🏯
Tuesday, November 13, 2018
HOUSE 🏛️PLAN DOUBLE FLAT DESIGN 2BHK ||2400 SQFT🏚️
https://m.youtube.com/watch?v=oHbJ94rWV7Y&feature=youtu.be
HOUSE 🏛️PLAN DOUBLE FLAT DESIGN
2BHK ||2400 SQFT🏚️
38×23 3bhk house🏣 plan||874 sqft side work ||south face🏢
https://m.youtube.com/watch?v=9GItELOJ00Q&feature=youtu.be
38×23 3bhk house🏣 plan||874 sqft
side work ||south face🏢
2bhk house🏠 plan & 900 sqft east face|| Low cost plan🏛️
https://m.youtube.com/watch?feature=youtu.be&v=0oBBy3auOnc
2bhk house🏠 plan & 900 sqft east face||
Low cost plan🏛️
Friday, November 9, 2018
FRONT ELEVATION||2D AUTOCAD DRAWING
https://m.youtube.com/watch?v=efXA3dIGP7A&noapp=1&client=mv-google
FRONT ELEVATION||2D AUTOCAD DRAWING
Thursday, November 8, 2018
Foundation layout plan & beam layout plan||
https://m.youtube.com/watch?feature=youtu.be&v=P6AgkCcKA70
Foundation layout plan & beam layout plan||
Foundation layout plan & beam layout plan||
Wednesday, November 7, 2018
Basic civil drawing AutoCAD tutorial
https://m.youtube.com/watch?feature=youtu.be&v=S1XyGDriwf8
Watch the video about basic civil engineering
Part -1(AutoCAD tutorial)
Monday, November 5, 2018
TECH HOUSE DESIGNER & AUTOCAD
https://www.youtube.com/channel/UCVj_paAhq0mWL1JjoyVxPNQ
TECH HOUSE 🏠DESIGNER & AUTOCAD
SUBSCRIBE THIS CHANNEL & LIKE & SHARE
Sunday, November 4, 2018
**15 TECHNICAL TERMS ABOUT REINFORCEMENT A CONSTRUCTION SUPERVISOR
=>
1: Concrete Cover for Reinforcement:-
Concrete cover is also called clear cover for reinforcement. and it is the distance b/w steel surface and nearest outer surface of concrete structure.
Concrete cover for different RCC members
Pile = 75 mm
Pile cap =75 mm
Footing = 75 mm
Column below ground = 65 mm
Column above ground = 40 mm
Shear wall below ground = 65 mm
Shear wall above ground = 40 mm
Beam below ground = 65 mm
Beam above ground = 40 mm
Slab below ground = 50 mm
Slab above ground = 20 mm
Stair = 20 mm
2: Unite Weight of Steel bar:-
Site supervisor should be know the unite weight of steel we have given weight of steel for different dia of steel
8 mm ø bar – 0.12 kg/ft
10 mm ø bar – 0.19 kg/ft
12 mm ø bar – 0.27 kg/ft
16 mm ø bar – 0.48 kg/ft
20 mm ø bar – 0.75 kg/ft
25 mm ø bar – 1.25 kg/ft
3: Lap in compression zone:-
Steel should be lapping for compression zone with 50d where ( d ) is dia of steel bar
4: Lapping for Tension:-
Steel should be lapping for tension zone with 40d where ( d ) is dia of steel bar
5: No Lapping:-
Lap should be not provide larger than 36mm dia of steel
6: Require bending wire:-
For binding one ton of MS bar 7 kg to 13 kg binding wire is required.
7: Standard length of Mild steel bar:-
Mild steel Standard length is 40′
8: Minimum Longitudinal Bar in a Column:-
Use Minimum 4 No’s of steel in Square column and 6 No’s for circular column
9: Placing Stirrup:-
Place 1st stirrup with the spacing of 2 inches.
10: Hook’s Angle of Stirrup:-
Stirrup’s hook angle is 135°.
11: Bend for Vertical Bar of Column:-
Remember that vertical column bars are called longitudinal bars, and bend is provide at one end of longitudinal bar with the angle of 90 degree and then length should be not less than 18 inches.
12: End Hook for Longitudinal Bar of Beam:-
Column end hook angel should be with 90 degree
13: Hook’s Length of Stirrup:-
The stirrup hook length should be not less than 3 inches or use this formula = 6d where d is dia of steel bar which used for stirrup.
14: Maximum Lap in a Zone:-
Don’t use more than 50% lapping zone in any RCC structure.
15: Bent Up bar:-
Provide bent up bar near at support of slab and beam.
=>
1: Concrete Cover for Reinforcement:-
Concrete cover is also called clear cover for reinforcement. and it is the distance b/w steel surface and nearest outer surface of concrete structure.
Concrete cover for different RCC members
Pile = 75 mm
Pile cap =75 mm
Footing = 75 mm
Column below ground = 65 mm
Column above ground = 40 mm
Shear wall below ground = 65 mm
Shear wall above ground = 40 mm
Beam below ground = 65 mm
Beam above ground = 40 mm
Slab below ground = 50 mm
Slab above ground = 20 mm
Stair = 20 mm
2: Unite Weight of Steel bar:-
Site supervisor should be know the unite weight of steel we have given weight of steel for different dia of steel
8 mm ø bar – 0.12 kg/ft
10 mm ø bar – 0.19 kg/ft
12 mm ø bar – 0.27 kg/ft
16 mm ø bar – 0.48 kg/ft
20 mm ø bar – 0.75 kg/ft
25 mm ø bar – 1.25 kg/ft
3: Lap in compression zone:-
Steel should be lapping for compression zone with 50d where ( d ) is dia of steel bar
4: Lapping for Tension:-
Steel should be lapping for tension zone with 40d where ( d ) is dia of steel bar
5: No Lapping:-
Lap should be not provide larger than 36mm dia of steel
6: Require bending wire:-
For binding one ton of MS bar 7 kg to 13 kg binding wire is required.
7: Standard length of Mild steel bar:-
Mild steel Standard length is 40′
8: Minimum Longitudinal Bar in a Column:-
Use Minimum 4 No’s of steel in Square column and 6 No’s for circular column
9: Placing Stirrup:-
Place 1st stirrup with the spacing of 2 inches.
10: Hook’s Angle of Stirrup:-
Stirrup’s hook angle is 135°.
11: Bend for Vertical Bar of Column:-
Remember that vertical column bars are called longitudinal bars, and bend is provide at one end of longitudinal bar with the angle of 90 degree and then length should be not less than 18 inches.
12: End Hook for Longitudinal Bar of Beam:-
Column end hook angel should be with 90 degree
13: Hook’s Length of Stirrup:-
The stirrup hook length should be not less than 3 inches or use this formula = 6d where d is dia of steel bar which used for stirrup.
14: Maximum Lap in a Zone:-
Don’t use more than 50% lapping zone in any RCC structure.
15: Bent Up bar:-
Provide bent up bar near at support of slab and beam.
Saturday, November 3, 2018
What is centre line method
* WHAT IS CENTRE LINE METHOD:-
=>
The center line method is suitable for wall cross sections. and the center line method the total length of centre line should be multiplying with breadth and depth of the any wall than it will give us the total quantity at the same time. and each length wall length should be measure to center line of the wall.
To fine out the quantity of wall or any construction building. And this method ( Centre line ) is useful for walls with equivalent cross sections. In order to obtain the total quantity instantly, the total centre line length is multiplied with breadth and depth of relevant item. When cross walls or partitions or verandah walls are attached with main wall, the length of the centre line decreases by half of breadth for each junction. Such junction or joints are analyzed cautiously at the time of estimating total centre line length.
*SOLUTION :-
--------------------
(1)Total Center line length = ?
(2)Now Quantity of Excavation
(3)Volume of Excavation = Total Centre line length x Breadth of Foundation x Depth of Foundation
(4)Volume of Excavation = ?
(5)Quantity of concrete in foundation = Total Centre line length x Breadth of Foundation x Depth of concrete.
(6)Quantity of concrete in foundation = ?
(7)Quantity of bricks in foundation = Total Centre line length x Breadth of Foundation x ( Total depth of foundation – concrete depth)
(8)Quantity of bricks in foundation =?
(9)Quantity of D.P.C = Total Centre line length x Breadth of Foundation x thickness of D.P.C suppose (25mm)
(10)Quantity of D.P.C = ?
(11)Quantity of plinth beam = Total Centre line length x Breadth of the beam x Depth of beam
(12)Quantity of plinth beam = ?
(13)Brick work in super structure = Total centre line length x breadth of wall x height of wall
(14)Brick work in super structure = ?
(15)Quantity of wall plaster for 2 sides = Total centre line length x height of wall x thickness of plaster
(16)Quantity of wall plaster for 2 sides = ?
(17)Quantity of Paint for 2 sides of wall = Total centre line length x height of wall x 2 = Area of paint in sft ( multiply 2 for wall 2 sides of wall.
(18)We have two kind of wall in the figure > Long wall and short wall
* Note:- The centre line method is the one of the best method to find out the building quantity. and this method is used at the construction site. therefore we have to learn the centre line method with long wall and short wall method. with this method we can find out the exact quantity of any construction building.
=>
The center line method is suitable for wall cross sections. and the center line method the total length of centre line should be multiplying with breadth and depth of the any wall than it will give us the total quantity at the same time. and each length wall length should be measure to center line of the wall.
To fine out the quantity of wall or any construction building. And this method ( Centre line ) is useful for walls with equivalent cross sections. In order to obtain the total quantity instantly, the total centre line length is multiplied with breadth and depth of relevant item. When cross walls or partitions or verandah walls are attached with main wall, the length of the centre line decreases by half of breadth for each junction. Such junction or joints are analyzed cautiously at the time of estimating total centre line length.
*SOLUTION :-
--------------------
(1)Total Center line length = ?
(2)Now Quantity of Excavation
(3)Volume of Excavation = Total Centre line length x Breadth of Foundation x Depth of Foundation
(4)Volume of Excavation = ?
(5)Quantity of concrete in foundation = Total Centre line length x Breadth of Foundation x Depth of concrete.
(6)Quantity of concrete in foundation = ?
(7)Quantity of bricks in foundation = Total Centre line length x Breadth of Foundation x ( Total depth of foundation – concrete depth)
(8)Quantity of bricks in foundation =?
(9)Quantity of D.P.C = Total Centre line length x Breadth of Foundation x thickness of D.P.C suppose (25mm)
(10)Quantity of D.P.C = ?
(11)Quantity of plinth beam = Total Centre line length x Breadth of the beam x Depth of beam
(12)Quantity of plinth beam = ?
(13)Brick work in super structure = Total centre line length x breadth of wall x height of wall
(14)Brick work in super structure = ?
(15)Quantity of wall plaster for 2 sides = Total centre line length x height of wall x thickness of plaster
(16)Quantity of wall plaster for 2 sides = ?
(17)Quantity of Paint for 2 sides of wall = Total centre line length x height of wall x 2 = Area of paint in sft ( multiply 2 for wall 2 sides of wall.
(18)We have two kind of wall in the figure > Long wall and short wall
* Note:- The centre line method is the one of the best method to find out the building quantity. and this method is used at the construction site. therefore we have to learn the centre line method with long wall and short wall method. with this method we can find out the exact quantity of any construction building.
Compound of road structures
*COMPOUND OF ROAD STRUCTURE:-
1: sub – Grade 2: Sub – Base 3: Base Course 4: Binder Course
5: Surfacing
(1)SUB GRADE:-
=>
Sub-grade is the the natural surface of the road, which is very important for road and this is lowest layer of the road.
Sub Grade construction:
this is the natural surface of the soil. therefore if the bearing capacity of soil is good so we have should not do any change in sub grade. but if the bearing capacity of soil is low than we have to up the sub grade level up to 60 cm (2ft) from the flood level. and we have to used the cheap materials in the sub grade just for making surface if the bearing capacity is good.
(2)SUB BASE :-
=>
Sub base is the one of the main load bearing layer of the road. which role is to spread the total load of the sub base to sub grade. and this is also the important layer of the road. And we have to used the good quality of materials in the sub base. because when the sub base is not good so the road will be not work for long time.
construction Sub Base:
The sub base can constructed above the sub grade. and the thickness of the sub base should be from 3 inch to 6 inch or 7.5cm to 15cm.
(3)Base Course:-
=>
the base course the pavements layer of material in asphalt road. and this layer in between the sub base and binder course. when the sub base designed than we directly construct the base course on above this.
Construction of Base Course
we have to use the strong materials in this layer of the road. and the bottom layer essentially comprises of unbound mixture from course and fin aggregate , and also used to crush sand, to get the desire load bearing capacity and absorb the upcoming traffic load.and we have to use the good quality of materials in the base course construction.
(4)Binder Course :-
=>
in road structure the binder course are the different combination of aggregate and binders. and the binder course is layer which bind all the materials in road structure. which are present in the base course , sub base and sub grade. in binder course we can bind the materials with asphalt (bitumen). and binder course is suitable for a wide range of of used from heavy duty of road pavement to car parks and also for race road etc.
(5)SURFACING :-
=>
Surfacing is the waterproof layer of road, which protect the underlying pavement. and also increase the skid resistance of road. the surfacing prevent the road from the cracks . and its anti- glare surface during the wet weather and surfacing can increase the reflexive surface for the night driving.
_______________________××_________________________
Saturday, October 27, 2018
Rcc slab design
*RCC Slab Design Guidelines:-
a) Effective span of slab:-
Effective span of slab shall be lesser of the two
1. L = clear span + d (effective depth )
2. L = Center to center distance between the support
b) Depth of slab:-
The depth of slab depends on bending moment and deflection criterion. the trail depth can be obtained using:
Effective depth d= Span /((L/d)Basic x modification factor)
For obtaining modification factor, the percentage of steel for slab can be assumed from 0.2 to 0.5%.
The effective depth d of two way slabs can also be assumed using cl.24.1,IS 456 provided short span is 3.5m and loading class is <3.5KN/m2
Type of support
Simply supported
Fe-250 – L/35
Fe-415 – L/28
Continuous support
Fe-250 – L/40
Fe-415 – L/32
Or, the following thumb rules can be used:
One way slab d=(L/22) to (L/28).
Two way simply supported slab d=(L/20) to (L/30)
Two way restrained slab d=(L/30) to (L/32)
c) Load on slab:-
The load on slab comprises of Dead load, floor finish and live load. The loads are calculated per unit area (load/m2).
Dead load = D x 25 kN/m2 ( Where D is thickness of slab in m)
Floor finish (Assumed as)= 1 to 2 kN/m2
Live load (Assumed as) = 3 to 5 kN/m2 (depending on the occupancy of the building)
*Detailing Requirements of RCC Slab as per IS456: 2000
a) Nominal Cover:-
For Mild exposure – 20 mm
For Moderate exposure – 30 mm
However, if the diameter of bar do not exceed 12 mm, or cover may be reduced by 5 mm. Thus for main reinforcement up to 12 mm diameter bar and for mild exposure, the nominal cover is 15 mm.
b) Minimum reinforcement:- The reinforcement in either direction in slab shall not be less than
0.15% of the total cross sectional area for Fe-250 steel
0.12% of the total cross-sectional area for Fe-415 & Fe-500 steel.
c) Spacing of bars:- The maximum spacing of bars shall not exceed
Main Steel – 3d or 300 mm whichever is smaller
Distribution steel –5d or 450 mm whichever is smaller Where, ‘d’ is the effective depth of slab. Note: The minimum clear spacing of bars is not kept less than 75 mm (Preferably 100 mm) though code do not recommend any value.
d) Maximum diameter of bar: -The maximum diameter of bar in slab, shall not exceed D/8, where D is the total thickness of slab.
a) Effective span of slab:-
Effective span of slab shall be lesser of the two
1. L = clear span + d (effective depth )
2. L = Center to center distance between the support
b) Depth of slab:-
The depth of slab depends on bending moment and deflection criterion. the trail depth can be obtained using:
Effective depth d= Span /((L/d)Basic x modification factor)
For obtaining modification factor, the percentage of steel for slab can be assumed from 0.2 to 0.5%.
The effective depth d of two way slabs can also be assumed using cl.24.1,IS 456 provided short span is 3.5m and loading class is <3.5KN/m2
Type of support
Simply supported
Fe-250 – L/35
Fe-415 – L/28
Continuous support
Fe-250 – L/40
Fe-415 – L/32
Or, the following thumb rules can be used:
One way slab d=(L/22) to (L/28).
Two way simply supported slab d=(L/20) to (L/30)
Two way restrained slab d=(L/30) to (L/32)
c) Load on slab:-
The load on slab comprises of Dead load, floor finish and live load. The loads are calculated per unit area (load/m2).
Dead load = D x 25 kN/m2 ( Where D is thickness of slab in m)
Floor finish (Assumed as)= 1 to 2 kN/m2
Live load (Assumed as) = 3 to 5 kN/m2 (depending on the occupancy of the building)
*Detailing Requirements of RCC Slab as per IS456: 2000
a) Nominal Cover:-
For Mild exposure – 20 mm
For Moderate exposure – 30 mm
However, if the diameter of bar do not exceed 12 mm, or cover may be reduced by 5 mm. Thus for main reinforcement up to 12 mm diameter bar and for mild exposure, the nominal cover is 15 mm.
b) Minimum reinforcement:- The reinforcement in either direction in slab shall not be less than
0.15% of the total cross sectional area for Fe-250 steel
0.12% of the total cross-sectional area for Fe-415 & Fe-500 steel.
c) Spacing of bars:- The maximum spacing of bars shall not exceed
Main Steel – 3d or 300 mm whichever is smaller
Distribution steel –5d or 450 mm whichever is smaller Where, ‘d’ is the effective depth of slab. Note: The minimum clear spacing of bars is not kept less than 75 mm (Preferably 100 mm) though code do not recommend any value.
d) Maximum diameter of bar: -The maximum diameter of bar in slab, shall not exceed D/8, where D is the total thickness of slab.
Friday, October 26, 2018
BEST INFO ABOUT BATHROOM SIZE AND SPACE ARRANGEMENT
BEST INFO ABOUT BATHROOM SIZE AND SPACE ARRANGEMENT
Maximum distance between two RCC columns
MAXIMUM DISTANCE BETWEEN TWO RCC COLUMNS?
Normal distance b/w two RCC columns is 5 meter Or 16 feet.
Maximum distance b/w RCC columns is 7.5 meter or 24 feet.
Minimum distance b/w 2 RCC columns is 2.5 meters or 8 feet.
Remember that for normal load such a domestic house we can take distance b/w 2 RCC columns = 5 meter.
If we take distance b/w two columns 7.5 meter than we will increase the width and depth of beam.
____________________________________________________
Normal distance b/w two RCC columns is 5 meter Or 16 feet.
Maximum distance b/w RCC columns is 7.5 meter or 24 feet.
Minimum distance b/w 2 RCC columns is 2.5 meters or 8 feet.
Remember that for normal load such a domestic house we can take distance b/w 2 RCC columns = 5 meter.
If we take distance b/w two columns 7.5 meter than we will increase the width and depth of beam.
____________________________________________________
How to calculate quantity of steel for beam
HOW TO CALCULATE QUANTITY OF STEEL FOR RCC BEAM , COLUMN AND SLAB?
WE KNOW THAT:
MINIMUM PERCENTAGE % OF STEEL AS PER INDIAN STANDARD ARE GIVEN BELOW.
1: For Column = 0.8% of Cross Section of Column
2: For Beam = As = 0.85bd / fy of cross section area. , where As for Area of steel.
3: For Slab = 0.12% of Total area of slab.
Maximum Steel as a per Indian Standard are given below.
For Column = 6% of Cross Sectional Area of Column
For Slab = 4% of Cross Sectional area of slab.
For Beam = 4 % of Cross sectional are of beam.
From above formulas you can find the quantity of steel for different structures.
________________________##_________________________
WE KNOW THAT:
MINIMUM PERCENTAGE % OF STEEL AS PER INDIAN STANDARD ARE GIVEN BELOW.
1: For Column = 0.8% of Cross Section of Column
2: For Beam = As = 0.85bd / fy of cross section area. , where As for Area of steel.
3: For Slab = 0.12% of Total area of slab.
Maximum Steel as a per Indian Standard are given below.
For Column = 6% of Cross Sectional Area of Column
For Slab = 4% of Cross Sectional area of slab.
For Beam = 4 % of Cross sectional are of beam.
From above formulas you can find the quantity of steel for different structures.
________________________##_________________________
How to find depth of foundation for building
HOW TO FIND DEPTH OF FOUNDATION FOR BUILDING?
**USE GIVEN FORMULA TO FIND DEPTH OF FOUNDATION:
From Rankine’s Formula,
Depth = p/w (1-sin$/1+sin$)
Where,
p=total load on foundation
w=unit wt of soil
$ = angle of repose of soil
____________________________________________________
**USE GIVEN FORMULA TO FIND DEPTH OF FOUNDATION:
From Rankine’s Formula,
Depth = p/w (1-sin$/1+sin$)
Where,
p=total load on foundation
w=unit wt of soil
$ = angle of repose of soil
____________________________________________________
REMEMBER SOME POINTS BEFORE STARTING CONCRETING IN FOOTING
REMEMBER SOME POINTS BEFORE STARTING CONCRETING IN FOOTING
Monday, October 8, 2018
Thursday, October 4, 2018
Wednesday, October 3, 2018
Thursday, September 27, 2018
Stress strain diagram
The stress-strain diagram is generally accepted as the plotted results of a tensile test completed under carefully controlled conditions on a speciman of a metal. The stress-strain diagram important for design engineers in that it establishes the physical properties of the material under test including the yield strength, the ultimate strength, the elongation at fracture, the elastic limit etc.
The test is carried out on a bar of uniform cross section, in a testing machine which indicates the tensile load being applied. The elongation of a calibrated length of the test piece (called the gauge length) is recorded by and extensometer or strain gauge.
The load is gradually increased until the specimen breaks.
The measured load results and the extension results are then converted to stress values (Load/specimen area) and strain values (extension / gauge length ) and the results are plotted on a graph. The stress levels resulting from this test are nominal or practical engineering values.
The tensile test does not provide any information as to the strength of a material under highly cyclic loading, and does not identify the resistance of the material to shock loading. Other test procedures are required to test these factors.
Different materials clearly result in different graphs. The notes that follow relate to these different graphs and the important data which is extracted from these graphs.
STRESS STRAIN DIAGRAM FOR MILD STEEL:
Saturday, September 1, 2018
Thursday, August 30, 2018
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